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An electron is accelerated from rest through a potential difference of 3.75 kV.It enters a region where a uniform 4.0-mT field is perpendicular to the velocity of the electron.Calculate the radius of the path this electron will follow in the magnetic field.(e = 1.60 × 10-19 C,melectron = 9.11 × 10-31 kg)
Standardized Work
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