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In the First Nuclear Reaction Observed,physicists Saw an Alpha Particle 55MeV55 \mathrm { MeV } \text {, }

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In the first nuclear reaction observed,physicists saw an alpha particle (Z = 2) interact with a nitrogen nucleus in air (Z = 7) to produce a proton.The energy of the alpha particle was 55MeV55 \mathrm { MeV } \text {, } enough to enable the nuclei to touch in spite of the Coulomb repulsion.What distance (in fm) between the centers of the alpha particle and the nitrogen was reached? This determines a limit on the radius of the nitrogen nucleus.(1 eV = 1.60 × 10-19 J,e = 1.60 × 10-19 C,1/4πε0 = 8.99 × 109 N ∙ m2/C2)


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