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Calculate the standard reaction enthalpy for the following reaction.
CH4(g) + H2O(g) CO(g) + 3H2(g)
Given:
2H2(g) + CO(g) CH3OH(l)
H° = -128.3 kJ.mol-1
2CH4(g) + O2(g) 2CH3OH(l)
H° = -328.1 kJ.mol-1
2H2(g) + O2(g) 2H2O(g)
H° = -483.6 kJ.mol-1
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