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Exhibit 12

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Exhibit 12.5
The following questions use the information below.
The owner of Sal's Italian Restaurant wants to study the growth of his business using simulation.He is interested in simulating the number of customers and the amount ordered by customers each month.He currently serves 1000 customers per month and feels this can vary uniformly between a decrease of as much as 5% and an increase of up to 9%.The bill for each customer is a normally distributed random variable with a mean of $20 and a standard deviation of $5.The average order has been increasing steadily over the years and the owner expects the mean order will increase by 2% per month.You have created the following spreadsheet to simulate the problem.
-Sal,from Exhibit 12.5,has produced the following spreadsheet to compute confidence intervals on his income.What formula should go in cell B12 to compute the upper limit on a 95% confidence interval for the population proportion below 90%?
 A B12 Sample Size: 30034 Sample Mean: 4,119,5195 Sample StandardDeviation 291,11767 95% LCL for the population mean: 4,086,5768 95% UCL for the population mean: 4,152,462910 Target Proportion 0.90011 95% Lower Confidence Limit: 0.86612 95% Upper Confidence Limit: 0.934\begin{array}{|c|c|c|}\hline & \text { A } & \mathrm{B} \\\hline 1 & & \\\hline 2 & \text { Sample Size: } & 300 \\\hline 3 & & \\\hline 4 & \text { Sample Mean: } & 4,119,519 \\\hline 5 & \text { Sample StandardDeviation } & 291,117 \\\hline 6 & & \\\hline 7 & \text { 95\% LCL for the population mean: } & 4,086,576 \\\hline 8 & \text { 95\% UCL for the population mean: } & 4,152,462 \\\hline 9 & & \\\hline 10 & \text { Target Proportion } & 0.900 \\\hline 11 & \text { 95\% Lower Confidence Limit: } & 0.866 \\\hline 12 & \text { 95\% Upper Confidence Limit: } & 0.934 \\\hline\end{array}


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