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Lithium and Nitrogen React to Produce Lithium Nitride: 6 Li(s)

question 171

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Lithium and nitrogen react to produce lithium nitride: 6 Li(s) + Lithium and nitrogen react to produce lithium nitride: 6 Li(s) +   (g) → 2 Li<sub>3</sub>N(s)  How many moles of   are needed to react with 0.550 mol of lithium? A)  3.30 B)  0.550 C)  0.183 D)  1.65 E)  0.0917 (g) → 2 Li3N(s)
How many moles of Lithium and nitrogen react to produce lithium nitride: 6 Li(s) +   (g) → 2 Li<sub>3</sub>N(s)  How many moles of   are needed to react with 0.550 mol of lithium? A)  3.30 B)  0.550 C)  0.183 D)  1.65 E)  0.0917 are needed to react with 0.550 mol of lithium?


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