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The Thermochemical Equation for the Combustion of Methanol Is Shown \to

question 26

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The thermochemical equation for the combustion of methanol is shown below.

CH3OH(  The thermochemical equation for the combustion of methanol is shown below.  CH<sub>3</sub>OH(   ) + 3/2 O<sub>2</sub>(g)  \to CO<sub>2</sub>(g) + 2 H<sub> 2</sub>O(g)   \Delta <sub>r</sub>H<sup> \circ </sup>= -638.7 kJ/mol-rxn What is the enthalpy change for the combustion of 8.59 g CH<sub>3</sub>OH? A)  -171 kJ B)  -19.9 kJ C)  -2.38  \times  10<sup>3</sup> kJ D)  -5.49  \times  10<sup>3</sup> kJ E)  -1.76  \times  10<sup>6</sup> kJ ) + 3/2 O2(g) \to CO2(g) + 2 H 2O(g)
Δ\Delta rH \circ = -638.7 kJ/mol-rxn
What is the enthalpy change for the combustion of 8.59 g CH3OH?


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