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Given the Following Equilibrium Constants,
Ka (HSO4-)= 1 ×\times 10-2
Kb (CH3CO2-)= 5

question 72

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Given the following equilibrium constants,
Ka (HSO4-) = 1.2 ×\times 10-2
Kb (CH3CO2-) = 5.6 ×\times 10-10
Kw = 1.00 ×\times 10-14
Determine the equilibrium constant for the reaction below at 25 \circ C.
HSO4-(aq) + CH3CO2-(aq)  Given the following equilibrium constants, K<sub>a</sub> (HSO<sub>4</sub><sup>-</sup>) = 1.2  \times  10<sup>-2</sup> K<sub>b</sub> (CH<sub>3</sub>CO<sub>2</sub><sup>-</sup>) = 5.6  \times  10<sup>-10</sup> K<sub>w</sub> = 1.00  \times  10<sup>-14</sup> Determine the equilibrium constant for the reaction below at 25 <sup> \circ </sup>C. HSO<sub>4</sub><sup>-</sup>(aq) + CH<sub>3</sub>CO<sub>2</sub><sup>-</sup>(aq)    SO<sub>4</sub><sup>2-</sup>(aq) + CH<sub>3</sub>CO<sub>2</sub>H(aq)  A)  6.7  \times  10<sup>-12</sup> B)  2.1  \times  10<sup>-7</sup> C)  1.5  \times  10<sup>-3</sup> D)  6.7  \times  10<sup>2</sup> E)  2.1  \times  10<sup>7</sup> SO42-(aq) + CH3CO2H(aq)


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