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What Is Ka at 25°C for the Following Equilibrium Given ×\times

question 39

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What is Ka at 25°C for the following equilibrium given Kb (CH3NH2) = 4.4 ×\times 10-4 at 25°C.?
CH3NH3+(aq) + H2O(l)  What is K<sub>a</sub> at 25°C for the following equilibrium given K<sub>b</sub><sup> </sup>(CH<sub>3</sub>NH<sub>2</sub>) = 4.4  \times  10<sup>-4</sup> at 25°C.? CH<sub>3</sub>NH<sub>3</sub><sup>+</sup>(aq) + H<sub>2</sub>O(l)    CH<sub>3</sub>NH<sub>2</sub>(aq) + H<sub>3</sub>O<sup>+</sup>(aq)  A)  4.4  \times  10<sup>-4</sup> B)  2.3  \times  10<sup>3</sup> C)  4.4  \times  10<sup>-10</sup> D)  4.4  \times  10<sup>4</sup> E)  2.3  \times  10<sup>-11</sup> CH3NH2(aq) + H3O+(aq)


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