Use the Definitions to Evaluate the Six Trigonometric Functions Of \theta

question 5

Multiple Choice

Use the definitions to evaluate the six trigonometric functions of $\theta$ . In cases in which a radical occurs in a denominator, rationalize the denominator.

• A) \(\sin \theta = \frac { \sqrt { 5 } } { 2 } , \tan \theta = \frac { 5 \sqrt { 5 } } { 2 } , \csc \theta = 5\) \(\cos \theta = \sqrt { 5 } , \cot \theta = \frac { \sqrt { 5 } } { 2 } , \sec \theta = \frac { 1 } { 5 }\)
• B) \(\sin \theta = \frac { \sqrt { 11 } } { 5 } , \tan \theta = \frac { 2 \sqrt { 11 } } { 7 } , \csc \theta = 2\) \(\cos \theta = \sqrt { 11 } , \cot \theta = \frac { \sqrt { 11 } } { 2 } , \sec \theta = \frac { 1 } { 7 }\)
• C) \(\sin \theta = \frac { 4 \sqrt { 5 } } { 5 } , \tan \theta = 4 , \csc \theta = \frac { \sqrt { 5 } } { 4 }\) \(\cos \theta = \frac { \sqrt { 5 } } { 2 } , \cot \theta = \frac { 1 } { 4 } , \sec \theta = \sqrt { 5 }\)
• D) \(\sin \theta = \frac { \sqrt { 5 } } { 5 } , \tan \theta = \frac { 1 } { 2 } , \csc \theta = \sqrt { 5 }\) \(\cos \theta = \frac { 2 \sqrt { 5 } } { 5 } , \cot \theta = 2 , \sec \theta = \frac { \sqrt { 5 } } { 2 }\)
• E) \(\sin \theta = \frac { \sqrt { 7 } } { 5 } , \tan \theta = \frac { 2 \sqrt { 7 } } { 5 } , \csc \theta = 2\) \(\cos \theta = \sqrt { 7 } , \cot \theta = \frac { \sqrt { 7 } } { 2 } , \sec \theta = \frac { 1 } { 2 }\)

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