Use Long Division to Find the Quotient and the Remainder $\frac { 6 x ^ { 3 } - 3 x + 3 } { 2 x + 1 }$

question 14

Multiple Choice

Use long division to find the quotient and the remainder. $\frac { 6 x ^ { 3 } - 3 x + 3 } { 2 x + 1 }$

• A) \(\text { quotient: } 3 x ^ { 2 } - \frac { 3 } { 2 } x - \frac { 3 } { 4 } ; \text { remainder: } \frac { 15 } { 4 }\)
• B) \(\text { quotient: } 3 x ^ { 2 } - \frac { 3 } { 2 } x + \frac { 1 } { 4 } ; \text { remainder: } \frac { 15 } { 4 }\)
• C) \(\text { quotient: } 15 x ^ { 2 } + \frac { 3 } { 2 } x - \frac { 1 } { 4 } ; \text { remainder: } \frac { 3 } { 4 }\)
• D) \(\text { quotient: } 3 x ^ { 2 } - \frac { 3 } { 2 } x - \frac { 3 } { 4 } ; \text { remainder: } - \frac { 15 } { 4 }\)
• E) \(\text { quotient: } 3 x ^ { 2 } - \frac { 3 } { 2 } x - \frac { 3 } { 4 } ; \text { remainder: } \frac { 7 } { 4 }\)

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