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The Size of an Animal Population at Time T Is N(t)=50,000+200sin7πt48\mathrm { N } ( \mathrm { t } ) = 50,000 + 200 \sin \frac { 7 \pi t } { 48 }

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The size of an animal population at time t is given by N(t)=50,000+200sin7πt48\mathrm { N } ( \mathrm { t } ) = 50,000 + 200 \sin \frac { 7 \pi t } { 48 } , where t is the number of months from June 1, 1980. At what rate is the animal population changing on June 1, 1981?
Enter your answer as a quotient reduced form ab\frac { a } { b } with π in the numerator (no units).

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