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Given f(x)=ln(x+1);0x1,n=3,f ( x ) = \ln ( x + 1 ) ; \quad 0 \leq x \leq 1 , n = 3 ,

question 34

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Given f(x)=ln(x+1);0x1,n=3,f ( x ) = \ln ( x + 1 ) ; \quad 0 \leq x \leq 1 , n = 3 , set up a Riemann sum to approximate the area under the graph of f(x) on the given interval. Use the midpoints. Is the following the correct answer?
ln(76)+ln(32)+ln(116)\ln \left( \frac { 7 } { 6 } \right) + \ln \left( \frac { 3 } { 2 } \right) + \ln \left( \frac { 11 } { 6 } \right)


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