Set Up an Integral or Sum of Integrals and Then $x ^ { 2 }$

question 42

Multiple Choice

Set up an integral or sum of integrals and then find the area bounded by y = $x ^ { 2 }$ + 3 and y = -5x - 3.

• A) \(\int _ { - 3 } ^ { - 2 } \left[ \left( x ^ { 2 } + 3 \right) - ( - 5 x - 3 ) \right] d x\) = - \(\frac { 1 } { 6 }\)
• B) \(\int _ { 2 } ^ { 3 } \left[ \left( x ^ { 2 } + 3 \right) - ( - 5 x - 3 ) \right] d x\) = \(\frac { 149 } { 6 }\)
• C) \(\int _ { - 3 } ^ { - 2 } \left[ ( - 5 x - 3 ) - \left( x ^ { 2 } + 3 \right) \right] d x\) = \(\frac { 1 } { 6 }\)
• D) \(\int _ { 2 } ^ { 3 } \left[ ( - 5 x - 3 ) - \left( x ^ { 2 } + 3 \right) \right] d x\) = - \(\frac { 149 } { 6 }\)
• E) none of these

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