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In the Figure Below, the Region Enclosed by the Curves 4x\frac { 4 } { x }

question 122

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In the figure below, the region enclosed by the curves y = - 4x\frac { 4 } { x } , y = -x, and y = -x + 3 is shown. Set up an integral or sum of integrals to find the area of the shaded region. (Do not calculate the area.)  In the figure below, the region enclosed by the curves y = -  \frac { 4 } { x }  , y = -x, and y = -x + 3 is shown. Set up an integral or sum of integrals to find the area of the shaded region. (Do not calculate the area.)    A)   \int _ { - 2 } ^ { - 1 } \left( - \frac { 4 } { x } + x \right)  d x  +  \int _ { - 1 } ^ { 2 } 3 d x  +  \int _ { 2 } ^ { 4 } \left( - x + 3 + \frac { 4 } { x } \right)  d x  B)   \int _ { - 2 } ^ { 2 } 3 \mathrm { dx } \int _ { 2 } ^ { 4 } \left( - x + 3 - \frac { 4 } { x } \right)  \mathrm { dx }  C)   \int _ { - 2 } ^ { 0 } \left( - \frac { 4 } { x } + x \right)  d x  +  \int _ { 0 } ^ { 2 } \left( - x + 3 + \frac { 4 } { x } \right)  d x  D)   \int _ { - 2 } ^ { 4 } 3 d x  E)  none of these


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