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Assume That a Culture of Bacteria Grows at a Rate 10610 ^ { 6 }

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Assume that a culture of bacteria grows at a rate proportional to its size such that if 10610 ^ { 6 } bacteria are present initially, then there are 2 × 10610 ^ { 6 } bacteria present after 3 hours. Determine a formula for the number of bacteria present after t hours in terms of powers of 2. (Hint: Recall that bxb ^ { x } = e(lnb)x\mathrm { e } ^ { ( \ln b ) x } .)Enter your answer exactly in the form P(x)=ab2c/d\mathrm { P } ( \mathrm { x } ) = \mathrm { a }^ b \cdot 2 ^{\mathrm { c } / \mathrm { d }}


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