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Use Implicit Differentiation to Determine dydx\frac { d y } { d x }

question 31

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Use implicit differentiation to determine dydx\frac { d y } { d x } where x3x ^ { 3 } + y3y ^ { 3 } = 2xy. Is dydx=2y3x23y22x\frac { d y } { d x } = \frac { 2 y - 3 x ^ { 2 } } { 3 y ^ { 2 } - 2 x } correct?

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