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A Person Throws a Die Until the Side with Two (56)n\left( \frac { 5 } { 6 } \right) ^ { n }

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A person throws a die until the side with two spots appears. The probability of throwing the die exactly n times before throwing a "2" is (56)n\left( \frac { 5 } { 6 } \right) ^ { n } (16)\left( \frac { 1 } { 6 } \right) , n ≥ 0. What is the probability that the number of throws before throwing a "2" is even? Enter just a reduced fraction.


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