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Given the Differential Equation y=e2t1y ^ { \prime } = e ^ { 2 t } - 1

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Given the differential equation: y=e2t1y ^ { \prime } = e ^ { 2 t } - 1 , is this the solution y=e2t2t+C?y = \frac { e ^ { 2 t } } { 2 } - t + C ?

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