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Given the Differential Equation dydt=t+ety\frac { \mathrm { dy } } { \mathrm { dt } } = \frac { \mathrm { t } + \mathrm { e } ^ { \mathrm { t } } } { \mathrm { y } } \text {, }

question 77

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Given the differential equation: dydt=t+ety\frac { \mathrm { dy } } { \mathrm { dt } } = \frac { \mathrm { t } + \mathrm { e } ^ { \mathrm { t } } } { \mathrm { y } } \text {, } is this the solution y=±t2+2et+C?y = \pm \sqrt { t ^ { 2 } + 2 e ^ { t } + C } ?


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