Given the Differential Equation with the Given Initial Condition $y ^ { \prime } = \frac { 3 t ^ { 2 } + 1 } { 2 y } ; \quad y ( 1 ) = - 5$

question 109

True/False

Given the differential equation with the given initial condition: $y ^ { \prime } = \frac { 3 t ^ { 2 } + 1 } { 2 y } ; \quad y ( 1 ) = - 5$ is this the solution $y = - \sqrt { t ^ { 3 } + t + 2 } ?$

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