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Given the Differential Equation $\left( t ^ { 2 } + 1 \right) y ^ { \prime } = y t$

question 66

question 66

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Given the differential equation: $\left( t ^ { 2 } + 1 \right) y ^ { \prime } = y t$ , is this the solution $y = c \sqrt { t ^ { 2 } + 1 } ?$

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