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Given yy ^ { \prime } = Y(y + 3) y(0)=4y ( 0 ) = - 4

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Given yy ^ { \prime } = y(y + 3). On a ty-coordinate system sketch the solutions corresponding to the initial conditions y(0)=4y ( 0 ) = - 4 , y(0)=1y ( 0 ) = - 1 , and y(0)=1y ( 0 ) = 1 . Does this graph represent the situation?  Given  y ^ { \prime }  = y(y + 3). On a ty-coordinate system sketch the solutions corresponding to the initial conditions  y ( 0 ) = - 4  ,  y ( 0 ) = - 1  , and  y ( 0 ) = 1  . Does this graph represent the situation?


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