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Find the First Derivative of Z = 4t + (3 2t+1\sqrt { 2 t + 1 }

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Short Answer

Find the first derivative of z = 4t + (3 - 2t+1\sqrt { 2 t + 1 } )3) ^ { 3 } at t = 32\frac { 3 } { 2 } .
Enter just a fraction of form ab\frac { a } { b } in lowest terms.

Understand the concepts of Type I and Type II errors and how changing levels of significance (α) and sample sizes (n) affect these errors.
Understand the definition, calculation, and interpretation of a test's power and its relationship to Type II errors.
Demonstrate the ability to calculate and interpret confidence intervals in the context of hypothesis testing.
Understand the relationship between sample size, significance level, and the power of a test.

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