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Find the First Derivative of Z = 4t + (3 2t+1\sqrt { 2 t + 1 }

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Short Answer

Find the first derivative of z = 4t + (3 - 2t+1\sqrt { 2 t + 1 } )3) ^ { 3 } at t = 32\frac { 3 } { 2 } .
Enter just a fraction of form ab\frac { a } { b } in lowest terms.

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