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A Round Loop of Diameter 12 Cm, Carrying a Current

question 6

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A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field   = 0.20 T î + 0.40 T ĵ. The normal to the loop is parallel to the unit vector   = -0.60 î - 0.80 ĵ. What is the potential energy of the loop? A)  -4.5 × 10<sup>-3</sup> J B)  +2.0 × 10<sup>-3</sup> J C)  -2.0 × 10<sup>-3</sup>J D)  -2.3 × 10<sup>-3</sup>J E)  +4.5 × 10<sup>-3</sup> J = 0.20 T î + 0.40 T ĵ. The normal to the loop is parallel to the unit vector A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field   = 0.20 T î + 0.40 T ĵ. The normal to the loop is parallel to the unit vector   = -0.60 î - 0.80 ĵ. What is the potential energy of the loop? A)  -4.5 × 10<sup>-3</sup> J B)  +2.0 × 10<sup>-3</sup> J C)  -2.0 × 10<sup>-3</sup>J D)  -2.3 × 10<sup>-3</sup>J E)  +4.5 × 10<sup>-3</sup> J
= -0.60 î - 0.80 ĵ. What is the potential energy of the loop?


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