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What Is the Disintegration Energy (In MeV)associated with This Spontaneous 60144Nd58140Ce+24He{ } _ { 60 } ^ { 144 } \mathrm { Nd } \rightarrow { } _ { 58 } ^ { 140 } \mathrm { Ce } + { } _ { 2 } ^ { 4 } \mathrm { He }

question 34

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What is the disintegration energy (in MeV) associated with this spontaneous decay? 60144Nd58140Ce+24He{ } _ { 60 } ^ { 144 } \mathrm { Nd } \rightarrow { } _ { 58 } ^ { 140 } \mathrm { Ce } + { } _ { 2 } ^ { 4 } \mathrm { He } mNd = 143.910 083 u mCe = 139.905 434 u
MHe = 4.002 603 u
1 u = 1.66 *10 - 27 kg


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