The Correct Form of Ampere's Law for Circuits with Gaps $\oint \mathrm { B } \cdot d \mathbf { s } = 0$

question 39

Multiple Choice

The correct form of Ampere's law for circuits with gaps in them is

• A) \(\oint \mathrm { B } \cdot d \mathbf { s } = 0\) .
• B) \(\oint \mathbf { B } \cdot d \mathbf { s } = I _ { \text {enciosed } }\) .
• C) \(\oint \mathbf { B } \cdot d \mathbf { s } = \mu _ { 0 } I _ { \text {enclosed } }\) .
• D) \(\oint \mathbf { B } \cdot d \mathbf { s } = \mu _ { 0 } I _ { \text {enclosed } } + \mu _ { 0 } \varepsilon _ { 0 } \frac { d \Phi _ { E } } { d t }\) .
• E) \(\oint \mathbf { B } \cdot d \mathbf { s } = \mu _ { 0 } I _ { \text {enclosed } } + \mu _ { 0 } \varepsilon _ { 0 } \frac { d \Phi _ { I } } { d t } - \frac { \varepsilon _ { 0 } } { \left( \mu _ { 0 } \right) ^ { 2 } } \frac { d \Phi _ { B } } { d t }\) .

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