If We Define the Gravitational Field $\overrightarrow { \mathbf { g } } = \frac { - G M _ { \text {source } } } { r ^ { 2 } } \hat { \mathbf { r } }$

question 22

Multiple Choice

If we define the gravitational field $\overrightarrow { \mathbf { g } } = \frac { - G M _ { \text {source } } } { r ^ { 2 } } \hat { \mathbf { r } }$ ,where $\hat{r}$ is a unit radial vector,then Gauss's Law for gravity is

• A) \(\oint \overrightarrow { \mathbf { g } } \cdot d \mathbf { A } = - G M _ { \text {source } }\) .
• B) \(\oint \overrightarrow { \mathbf { g } } \cdot d \mathbf { A } = + G M _ { \text {source } }\) .
• C) \(\oint \overrightarrow { \mathbf { g } } \cdot d \mathbf { A } = - 4 \pi G M _ { \text {source } }\) .
• D) \(\oint \overrightarrow { \mathbf { g } } \cdot d \mathbf { A } = + 4 \pi G M _ { \text {source } }\) .
• E) \(\oint \overrightarrow { \mathbf { g } } \cdot d \mathbf { A } = - 4 \pi G M _ { \text {source } } m _ { \text {object } }\) .

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