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Knowing That g=9.80ms2g = 9.80 \frac { \mathrm { m } } { \mathrm { s } ^ { 2 } }

question 40

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Knowing that g=9.80ms2g = 9.80 \frac { \mathrm { m } } { \mathrm { s } ^ { 2 } } at sea level and that RE = 6.37 * 106 m,we find that the value of g in ms2\frac { \mathrm { m } } { \mathrm { s } ^ { 2 } } at a distance RE from the surface of the Earth is


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