A 30-Kg Particle Has a Position Vector Given By By \overrightarrow

question 56

Multiple Choice

A 3.0-kg particle has a position vector given by $\overrightarrow { \mathbf { r } } = \left( 2.0 t ^ { 2 } \hat { \mathbf { i } } + 3.0 \hat { \mathbf { j } } \right)$ where $\overrightarrow { \mathbf { r } }$ is in meters and t is in seconds.What is the angular momentum of the particle,in kg.m²/s,about the origin at t = 2 s?

• A)72 \(\hat { k }\)
• B)-72 \(\hat { k }\)
• C)24 \(\hat { k }\)
• D)-24 \(\hat { k }\)
• E)22 \(\hat { k }\)

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