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A Particle Moves in the Xy Plane with a Constant a=4.0j^m/s2\overrightarrow { \mathbf { a } } = - 4.0 \hat { \mathbf { j } } \mathrm { m } / \mathrm { s } ^ { 2 }

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A particle moves in the xy plane with a constant acceleration given by a=4.0j^m/s2\overrightarrow { \mathbf { a } } = - 4.0 \hat { \mathbf { j } } \mathrm { m } / \mathrm { s } ^ { 2 } .At t = 0,its position and velocity are 10 i? and (2.0i~+8.0j~) m/s( - 2.0 \tilde { \mathbf { i } } + 8.0 \tilde { \mathbf { j } } ) \mathrm { m } / \mathrm { s } ,respectively.What is the distance from the origin to the particle at t = 2.0 s?

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