The Equation That Solves a Problem Is The Problem Is:
A)How Far Above Its Initial Position Does

question 33

Multiple Choice

The equation that solves a problem is $$6.4 \mathrm {~m} = 20 \mathrm {~m} + 3.0 \frac { \mathrm { m } } { \mathrm { s } } ( 2.0 \mathrm {~s} ) - 4.9 \frac { \mathrm { m } } { \mathrm { s } ^ { 2 } } ( 2.0 \mathrm {~s} ) ^ { 2 }$$ .The problem is:

• A)How far above its initial position does a rock travel in 2.0 s when thrown up from a point 40 m above the ground?
• B)How far below its initial position does a rock travel in 2.0 s when thrown up from a point 40 m above the ground?
• C)What is the position relative to the ground of a rock thrown up at 3.0 m/s from a roof 20 m above the ground 2.0 s after it is released?
• D)What is the change in position relative to the ground of a rock thrown up at 3.0 m/s from a roof 20 m above the ground 2.0 s after it is released?
• E)What is the position relative to the ground of a rock thrown up at 3.0 m/s from a roof 20 m above the ground if its maximum height is 33.6 m?

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