Solve the System Using Gauss-Jordan Elimination$$\left\{ \begin{aligned}
x + y + 2 z + t & = 62 \
x + 2 y + z + t & = 62 \
2 x + y + z + t & = 49 \
x + y + z + 2 t & = 62
\end{aligned} \right.$$

Question

Examlex · Accepted Answer

The Answer of Solve the System Using Gauss-Jordan Elimination$$\left\{ \begin{aligned}
x + y + 2 z + t & = 62 \
x + 2 y + z + t & = 62 \
2 x + y + z + t & = 49 \
x + y + z + 2 t & = 62
\end{aligned} \right.$$

Solve the System Using Gauss-Jordan Elimination $\left\{ \begin{aligned}x + y + 2 z + t & = 62 \\x + 2 y + z + t & = 62 \\2 x + y + z + t & = 49 \\x + y + z + 2 t & = 62\end{aligned} \right.$

Definitions:

Solve the System Using Gauss-Jordan Elimination {x+y+2z+t=62x+2y+z+t=622x+y+z+t=49x+y+z+2t=62\left\{ \begin{aligned}x + y + 2 z + t & = 62 \\x + 2 y + z + t & = 62 \\2 x + y + z + t & = 49 \\x + y + z + 2 t & = 62\end{aligned} \right.⎩⎨⎧​x+y+2z+tx+2y+z+t2x+y+z+tx+y+z+2t​=62=62=49=62​

Definitions:

Solve the System Using Gauss-Jordan Elimination $\left\{ \begin{aligned}x + y + 2 z + t & = 62 \\x + 2 y + z + t & = 62 \\2 x + y + z + t & = 49 \\x + y + z + 2 t & = 62\end{aligned} \right.$