Find the Minimum Value of the Objective Function and Where $\left( \frac { 22 } { 3 } , \frac { 19 } { 6 } \right)$

question 38

Multiple Choice

Find the minimum value of the objective function and where it occurs,subject to the constraints: ?
Objective function:
?
Z = 5x + 6y
?
Constraints:
?
X ? 0
Y ? 0
X + 4y ? 20
X + y ? 18
?2x + 2y ? 21
?

• A)Minimum at (0,0): 0
• B)Minimum at \(\left( \frac { 22 } { 3 } , \frac { 19 } { 6 } \right)\) : \(\frac { 167 } { 3 }\)
• C)Minimum at \(\left( 0 , \frac { 19 } { 6 } \right)\) : 19
• D)Minimum at \(\left( \frac { 22 } { 3 } , 0 \right)\) : \(\frac { 110 } { 3 }\)
• E)No minimum

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