Find the Exact Solutions of the Given Equation in the Interval

question 49

Multiple Choice

Find the exact solutions of the given equation in the interval [0,2π) . ​​ $$2 \sin ^ { 2 } x + 3 \sin x = - 1$$ ​

• A)​ \(x = \pi , \frac { 7 \pi } { 4 } , \frac { 3 \pi } { 2 } , \frac { 11 \pi } { 6 }\)
• B)​ \(x = \frac { 7 \pi } { 4 } , \frac { 3 \pi } { 2 } , \frac { 11 \pi } { 4 }\)
• C)​ \(x = \frac { 7 \pi } { 6 } , \frac { 3 \pi } { 2 } , \frac { 11 \pi } { 6 }\)
• D)​ \(x = \frac { \pi } { 4 } , \frac { 7 \pi } { 6 } , \frac { 3 \pi } { 2 } , \frac { 11 \pi } { 2 }\)
• E)​ \(x = 0 , \frac { 7 \pi } { 2 } , \frac { 3 \pi } { 2 } , \frac { 11 \pi } { 2 }\)

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