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The Range of a Projectile Fired at an Angle θ r=132v02sin2θr = \frac { 1 } { 32 } v _ { 0 } ^ { 2 } \sin 2 \theta

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The range of a projectile fired at an angle θ with the horizontal and with an initial velocity of v0 feet per second is r=132v02sin2θr = \frac { 1 } { 32 } v _ { 0 } ^ { 2 } \sin 2 \theta where r is measured in feet.A golfer strikes a golf ball at 90 feet per second.Ignoring the effects of air resistance,at what angle must the golfer hit the ball so that it travels 150 feet? (Round your answer to the nearest degree. )


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