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A Weight Is Attached to a Spring Suspended Vertically from a Ceiling.When

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A weight is attached to a spring suspended vertically from a ceiling.When a driving force is applied to the system,the weight moves vertically from its equilibrium position,and this motion is modeled by​ y=18sin2t+16cos2ty = \frac { 1 } { 8 } \sin 2 t + \frac { 1 } { 6 } \cos 2 t ​ where y is the distance from equilibrium (in feet) and t is the time (in seconds) .

Use the identity asinBθ+bcosBθ=a2+b2sin(Bθ+C) a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \sin ( B \theta + C ) where C=arctan(b/a) ,a>0C = \arctan ( b / a ) , a > 0 ,to write the model in the form y=a2+b2sin(Bt+C) y = \sqrt { a ^ { 2 } + b ^ { 2 } } \sin ( B t + C ) .


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