Use the Formula $a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C )$

question 14

Multiple Choice

Use the formula $a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C )$ ,where $C = \arctan ( a / b ) , a > 0$ ,to rewrite the trigonometric expression in the form.​ $\sqrt { 6 } \sin \left( \theta + \frac { \pi } { 4 } \right)$ ​

• A) \[\sqrt { 3 } \sin \theta - \sqrt { 3 } \cos \theta\]
• B) \[\sqrt { 3 } \sin \theta + \cos \theta\]
• C) \(\sin \theta - \sqrt { 3 } \cos \theta\)
• D) \(\sqrt { 3 } \sin \theta + \sqrt { 3 } \cos \theta\)
• E) \(\sin \theta + \cos \theta\)

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