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Use Inverse Functions Where Needed to Find All Solutions (If 2cos2xcosx1=02 \cos ^ { 2 } x - \cos x - 1 = 0

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Use inverse functions where needed to find all solutions (if they exist) of the given equation on the interval [0,2π) .​ 2cos2xcosx1=02 \cos ^ { 2 } x - \cos x - 1 = 0


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