Find the Inverse Function Of $f ( x ) = \sqrt { 36 - x ^ { 2 } } , 0 \leq x \leq 6$

question 31

Multiple Choice

Find the inverse function of $f ( x ) = \sqrt { 36 - x ^ { 2 } } , 0 \leq x \leq 6$ . ?

• A) \(f ^ { - 1 } ( x ) = \sqrt { 36 - x ^ { 2 } } , 0 \leq x \leq 6\)
• B) \(f ^ { - 1 } ( x ) = \sqrt { x ^ { 2 } - 36 } , 0 \leq x \leq 6\)
• C) \(f ^ { - 1 } ( x ) = 36 - x ^ { 2 } , 0 \leq x \leq 6\)
• D) \(f ^ { - 1 } ( x ) = \sqrt { 36 + x ^ { 2 } } , 0 \leq x \leq 6\)
• E) \(f ^ { - 1 } ( x ) = 36 + x ^ { 2 } , 0 \leq x \leq 6\)

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