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Use the Following Results the Polar Equation of the Hyperbolla x2a2y2b2=1\frac { x ^ { 2 } } { a ^ { 2 } } - \frac { y ^ { 2 } } { b ^ { 2 } } = 1

question 45

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Use the following results the polar equation of the hyperbolla x2a2y2b2=1\frac { x ^ { 2 } } { a ^ { 2 } } - \frac { y ^ { 2 } } { b ^ { 2 } } = 1 is r2=b21e2cos2θr ^ { 2 } = \frac { - b ^ { 2 } } { 1 - e ^ { 2 } \cos ^ { 2 } \theta } to write the polar form of the equation of the conic x216y29=1\frac { x ^ { 2 } } { 16 } - \frac { y ^ { 2 } } { 9 } = 1 . ​


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