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Use the Figure to Answer the Question $\theta$ )- ½ G (2

question 11

Multiple Choice

Use the figure to answer the question.
The figure represents the parabolic trajectory of a ball going from a to e in Earth gravity but without air resistance. The initial velocity of the ball is V_o at an angle $Use the figure to answer the question. The figure represents the parabolic trajectory of a ball going from a to e in Earth gravity but without air resistance. The initial velocity of the ball is Vo at an angle to the horizon. The vertical dashed lines represent equal time interval, -The vertical velocity at point b is: Note: (g = 9.81 m/s2) A) 0 B) Vo cos ( \theta ) - ½ g (2 \Delta t) 2 C) Vo sin ( \theta ) - ½ g (2 \Delta t) 2 D) Vo sin ( \theta ) + ½ g (2 \Delta t) 2 E) Vo cos ( \theta ) + ½ g (2 \Delta t) 2$ to the horizon. The vertical dashed lines represent equal time interval, $Use the figure to answer the question. The figure represents the parabolic trajectory of a ball going from a to e in Earth gravity but without air resistance. The initial velocity of the ball is Vo at an angle to the horizon. The vertical dashed lines represent equal time interval, -The vertical velocity at point b is: Note: (g = 9.81 m/s2) A) 0 B) Vo cos ( \theta ) - ½ g (2 \Delta t) 2 C) Vo sin ( \theta ) - ½ g (2 \Delta t) 2 D) Vo sin ( \theta ) + ½ g (2 \Delta t) 2 E) Vo cos ( \theta ) + ½ g (2 \Delta t) 2$
$Use the figure to answer the question. The figure represents the parabolic trajectory of a ball going from a to e in Earth gravity but without air resistance. The initial velocity of the ball is Vo at an angle to the horizon. The vertical dashed lines represent equal time interval, -The vertical velocity at point b is: Note: (g = 9.81 m/s2) A) 0 B) Vo cos ( \theta ) - ½ g (2 \Delta t) 2 C) Vo sin ( \theta ) - ½ g (2 \Delta t) 2 D) Vo sin ( \theta ) + ½ g (2 \Delta t) 2 E) Vo cos ( \theta ) + ½ g (2 \Delta t) 2$
-The vertical velocity at point b is: Note: (g = 9.81 m/s²)

Use the Figure to Answer the Question θ\thetaθ )- ½ G (2

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Use the Figure to Answer the Question $\theta$ )- ½ G (2