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Two Masses M and M (M > M)are Hung Over

question 53

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Two masses M and m (M > m) are hung over a disc (Idisc = Two masses M and m (M > m) are hung over a disc (I<sub>dis</sub><sub>c</sub> =   M'R<sup>2</sup>) and are released so that they accelerate.If T<sub>1</sub> is the tension in the cord on the left and T<sub>2</sub> is the tension in the cord on the right,then   A) T<sub>1</sub> = T<sub>2 </sub> B) T<sub>2</sub> > T<sub>1 </sub> C) T<sub>2</sub> < T<sub>1 </sub> D) T<sub>2</sub> = Mg E) T<sub>2</sub> = Mg/m M'R2) and are released so that they accelerate.If T1 is the tension in the cord on the left and T2 is the tension in the cord on the right,then Two masses M and m (M > m) are hung over a disc (I<sub>dis</sub><sub>c</sub> =   M'R<sup>2</sup>) and are released so that they accelerate.If T<sub>1</sub> is the tension in the cord on the left and T<sub>2</sub> is the tension in the cord on the right,then   A) T<sub>1</sub> = T<sub>2 </sub> B) T<sub>2</sub> > T<sub>1 </sub> C) T<sub>2</sub> < T<sub>1 </sub> D) T<sub>2</sub> = Mg E) T<sub>2</sub> = Mg/m


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