In Simple Harmonic Motion,the Displacement X = a Cos $\omega$ T and the Acceleration a = -

question 102

Multiple Choice

In simple harmonic motion,the displacement x = A cos $\omega$ t and the acceleration a = - $\omega$ ²x.If A = 0.25 m and the period is 0.32 s,the acceleration when t = 0.12 s is

• A)zero
• B)+3.9 m/s²
• C)-3.9 m/s²
• D)+6.8 m/s²
• E)-6.8 m/s²

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