A 05-Kg Mass Is Suspended from a Massless Spring That Has

question 35

Multiple Choice

A 0.5-kg mass is suspended from a massless spring that has a force constant of 79 N/m.The mass is displaced 0.1m down from its equilibrium position and released.If the downward direction is negative,the displacement of the mass as a function of time is given by

• A)y = 0.1 cos(158t - \(\pi\))
• B)y = 0.2 cos(158t - \(\pi\))
• C)y = 0.1 cos(12.6t - \(\pi\))
• D)y = 0.2 cos(12.6t + \(\pi\))
• E)y = 0.1 cos(2t + \(\pi\))

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