In the Previous Problem, Separate Variables Using $u ( r , \theta ) = R ( r ) \Theta ( \theta )$

question 5

Multiple Choice

In the previous problem, separate variables using $u ( r , \theta ) = R ( r ) \Theta ( \theta )$ . The resulting problems are

• A) \(r ^ { 2 } R ^ { \prime \prime } + r R ^ { \prime } - \lambda R = 0 , \Theta ^ { \prime \prime } - \lambda \Theta = 0 , \Theta ( \theta ) = \Theta ( \theta + 2 \pi )\)
• B) \(r ^ { 2 } R ^ { \prime \prime } + r R ^ { \prime } + \lambda R = 0 , \Theta ^ { \prime \prime } + \lambda \Theta = 0 , \Theta ( \theta ) = \Theta ( \theta + 2 \pi )\)
• C) \(r ^ { 2 } R ^ { \prime \prime } + r R ^ { \prime } - \lambda R = 0 , \Theta ^ { \prime \prime } + \lambda \Theta = 0 , \Theta ( \theta ) = \Theta ( \theta + 2 \pi )\)
• D) \(r ^ { 2 } R ^ { \prime \prime } + r R ^ { \prime } - \lambda R = 0 , \Theta ^ { \prime \prime } + \lambda \Theta = 0 , \Theta ( \theta ) = \Theta ( \theta + \pi )\)
• E) \(r ^ { 2 } R ^ { \prime \prime } + r R ^ { \prime } + \lambda R = 0 , \Theta ^ { \prime \prime } + \lambda \Theta = 0 , \Theta ( \theta ) = \Theta ( \theta + \pi )\)

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