The Solution of the Eigenvalue Problem from the Previous Problem $\lambda = n \pi / L , X ( x ) = \sin ( n \pi x / L ) , n = 1,2,3 , \ldots$

question 23

Multiple Choice

The solution of the eigenvalue problem from the previous problem is

• A) \(\lambda = n \pi / L , X ( x ) = \sin ( n \pi x / L ) , n = 1,2,3 , \ldots\)
• B) \(\lambda = n \pi / L , X ( x ) = \cos ( n \pi x / L ) , n = 0,1,2 , \ldots\)
• C) \(\lambda = ( n - 1 / 2 ) \pi / L , X ( x ) = \sin ( ( n - 1 / 2 ) \pi x / L ) , n = 1,2,3 , \ldots\)
• D) \(\lambda = ( ( n - 1 / 2 ) \pi / L ) ^ { 2 } , X ( x ) = \sin ( ( n - 1 / 2 ) \pi x / L ) , n = 1,2,3 , \ldots\)
• E) \(\lambda = ( ( n - 1 / 2 ) \pi / L ) ^ { 2 } , X ( x ) = \cos ( ( n - 1 / 2 ) \pi x / L ) , n = 1,2,3 , \ldots\)

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