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The Solution Of y+xyy=0,y(0)=0,y(0)=1y ^ { \prime \prime } + x y y ^ { \prime } = 0 , y ( 0 ) = 0 , y ^ { \prime } ( 0 ) = 1

question 38

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The solution of y+xyy=0,y(0) =0,y(0) =1y ^ { \prime \prime } + x y y ^ { \prime } = 0 , y ( 0 ) = 0 , y ^ { \prime } ( 0 ) = 1 for y(0.1) y ( 0.1 ) , using the Runge-Kutta method of order four, and using h=0.1h = 0.1 , is


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