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Using the Adams-Bashforth Method from the Previous Problem, and Using y0=1,y1=1.1052,y2=1.2214,y3=1.3499y _ { 0 } = 1 , y _ { 1 } = 1.1052 , y _ { 2 } = 1.2214 , y _ { 3 } = 1.3499

question 6

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Using the Adams-Bashforth method from the previous problem, and using the values y0=1,y1=1.1052,y2=1.2214,y3=1.3499y _ { 0 } = 1 , y _ { 1 } = 1.1052 , y _ { 2 } = 1.2214 , y _ { 3 } = 1.3499 the solution y=y,y(0) =1y ^ { \prime } = y , y ( 0 ) = 1 for yn+1=y(0.4) y _ { n + 1 } ^ { * } = y ( 0.4 ) with h=0.1h = 0.1 is


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