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For the Differential Equation (x24)3y2xy+y=0\left( x ^ { 2 } - 4 \right) ^ { 3 } y ^ { \prime \prime } - 2 x y ^ { \prime } + y = 0

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For the differential equation (x24) 3y2xy+y=0\left( x ^ { 2 } - 4 \right) ^ { 3 } y ^ { \prime \prime } - 2 x y ^ { \prime } + y = 0 , the point x=2x = - 2 is


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